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  • Don’t you mean if (!set1.hasOwnProperty(key))?
    – Gumbo
    Commented Oct 18, 2009 at 8:56
  • 2
    Why would I mean that? The purpose of that condition is to ignore properties that may be in the object's prototype. Commented Oct 18, 2009 at 19:13
  • It is not efficient to convert to objects in every use case. For example, we might want the union of keys from 2 arrays of Object.keys().
    – OXiGEN
    Commented Feb 9, 2021 at 23:20