Revisions to Loop through an array in JavaScript

Active reading [<https://www.wikihow.com/Use-Than-and-Then> <https://www.youtube.com/watch?v=1Dax90QyXgI&t=0m38s> <https://en.wikipedia.org/wiki/Sentence_clause_structure#Run-on_sentences> (see also <https://twitter.com/PeterMortensen/status/1199839973215739907>)].

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edited Oct 30, 2020 at 8:16

Peter Mortensen

31.3k
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The optimized approach is to cache the length of array and using the single varvariable pattern, initializing all variables with a single varvar keyword.

var i, max, myStringArray = ["Hello", "World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]); 

    // Do something
}

If the order of iteration does not matter thanthen you should try reversed loop, it. It is the fastest as it reducereduces overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

orOr better and cleaner to use whilea while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // doDo something with fruits[i]
}

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

The optimized approach is to cache the length of array and using the single variable pattern, initializing all variables with a single var keyword.

var i, max, myStringArray = ["Hello", "World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]); 

    // Do something
}

If the order of iteration does not matter then you should try reversed loop. It is the fastest as it reduces overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

Or better and cleaner to use a while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // Do something with fruits[i]
}

Post Undeleted by Brad Larson♦

occurred Feb 3, 2014 at 16:38

deleted 79 characters in body

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edited Feb 2, 2014 at 10:37

Zaheer Ahmed

28.4k
12
76
111

Here is detailed about optimization of loops in JavaScript In my blog.

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

Here is detailed about optimization of loops in JavaScript In my blog.

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

Post Deleted by Bill the Lizard

occurred Feb 2, 2014 at 3:15

added 11 characters in body

Source Link

edited Jan 13, 2014 at 7:43

Zaheer Ahmed

28.4k
12
76
111

Here is detailed about optimization of loops in JavaScript In my blog.

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

Here is detailed about optimization of loops in JavaScript.

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

Here is detailed about optimization of loops in JavaScript In my blog.

The optimized approach is to cache the length of array and using single var pattern initializing all variables with single var keyword.

var i, max, myStringArray = ["Hello","World"];
for (i = 0, max = myStringArray.length; i < max; i++) {
    alert(myStringArray[i]);
   //Do something
}

If order of iteration does not matter than you should try reversed loop, it is fastest as it reduce overhead condition testing and decrement is in one statement:

var i,myStringArray = ["item1","item2"];
for (i =  myStringArray.length; i--) {
    alert(myStringArray[i]);
}

or better and cleaner to use while loop:

var myStringArray = ["item1","item2"],i = myStringArray.length;
while(i--) {
   // do something with fruits[i]
}

Source Link

created Jan 11, 2014 at 20:53

Zaheer Ahmed

28.4k
12
76
111

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