Revisions to How to merge two arrays in JavaScript and de-duplicate items

Active reading - but more work is needed, e.g. near "want without duplicate".

Source Link

edited Oct 18, 2017 at 6:49

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132

Best Solution.The best solution...

youYou can check directly in the browser Consoleconsole by hitting...

Without Duplicate###Without duplicate

a = [1, 2, 3];
b = [3, 2, 1, "prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

With Duplicate###With duplicate

["prince", "asish", 5].concat(["ravi", 4])

ifIf you Want Without Duplicatewant without duplicate you can try a better Sol.solution from here - Shouting Code.

[1, 2, 3].concat([3, 2, 1, "prince"].filter(function(el) {
        return [1, 2, 3].indexOf(el) === -1;
    }));

Try Onon Chrome Browser Consolebrowser console

 f12 > console

OutPutOutput:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

Best Solution....

you can check directly in browser Console by hitting...

Without Duplicate

a = [1,2,3];
b = [3,2,1,"prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

With Duplicate

["prince","asish",5].concat(["ravi",4])

if you Want Without Duplicate you can try better Sol. from here - Shouting Code

[1,2,3].concat([3,2,1,"prince"].filter(function(el) {
        return [1,2,3].indexOf(el) === -1;
    }));

Try On Chrome Browser Console

 f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

The best solution...

You can check directly in the browser console by hitting...

###Without duplicate

a = [1, 2, 3];
b = [3, 2, 1, "prince"];

a.concat(b.filter(function(el) {
    return a.indexOf(el) === -1;
}));

###With duplicate

["prince", "asish", 5].concat(["ravi", 4])

If you want without duplicate you can try a better solution from here - Shouting Code.

[1, 2, 3].concat([3, 2, 1, "prince"].filter(function(el) {
    return [1, 2, 3].indexOf(el) === -1;
}));

Try on Chrome browser console

 f12 > console

Output:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

correction........

Source Link

edited Apr 14, 2016 at 8:17

Zigri2612

2.3k
21
33

Its Working fine aBest Solution.concat(b); With Duplicate...

you can check directly in browser Console by hitting...

Without Duplicate

a = [1,2,3];
b = [3,2,1,"prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

With Duplicate

["prince","asish",5].concat(["ravi",4])

if you Want Without Duplicate you can try better Sol. from here - Shouting Code

a = [1,2,3];
b = 3].concat([3,2,1,"prince"];

a.concat(b"prince"].filter(function(el) {
        return a[1,2,3].indexOf(el) === -1;
    }));

Try On Chrome Browser Console

 f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

Its Working fine a.concat(b); With Duplicate

you can check directly in browser Console by hitting...

["prince","asish",5].concat(["ravi",4])

if you Want Without Duplicate you can try better Sol. from here - Shouting Code

a = [1,2,3];
b = [3,2,1,"prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

Try On Chrome Browser Console

 f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

Best Solution....

you can check directly in browser Console by hitting...

Without Duplicate

a = [1,2,3];
b = [3,2,1,"prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

With Duplicate

["prince","asish",5].concat(["ravi",4])

if you Want Without Duplicate you can try better Sol. from here - Shouting Code

[1,2,3].concat([3,2,1,"prince"].filter(function(el) {
        return [1,2,3].indexOf(el) === -1;
    }));

Try On Chrome Browser Console

 f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

added 281 characters in body

Source Link

edited Apr 13, 2016 at 12:01

Zigri2612

2.3k
21
33

Its Working fine a.concat(b); With Duplicate

you can check directly in browser Console by hitting...

["prince","asish",5].concat(["ravi",4])

on browser console f12 > consoleif you Want Without Duplicate you can try better Sol. from here - Shouting Code

a = [1,2,3];
b = [3,2,1,"prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

Try On Chrome Browser Console

 f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

Its Working fine a.concat(b);

you can check directly in browser Console by hitting...

["prince","asish",5].concat(["ravi",4])

on browser console f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

Its Working fine a.concat(b); With Duplicate

you can check directly in browser Console by hitting...

["prince","asish",5].concat(["ravi",4])

if you Want Without Duplicate you can try better Sol. from here - Shouting Code

a = [1,2,3];
b = [3,2,1,"prince"];

a.concat(b.filter(function(el) {
        return a.indexOf(el) === -1;
    }));

Try On Chrome Browser Console

 f12 > console

OutPut:

["prince", "asish", 5, "ravi", 4]

[1, 2, 3, "prince"]

Source Link

created Mar 22, 2016 at 5:17

Zigri2612

2.3k
21
33

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