Revisions to How to merge two arrays in JavaScript and de-duplicate items

grammar fix

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edited May 4, 2021 at 13:13

SimplifiedI simplified the best of this answer and turned it into a nice function:

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

Simplified best of this answer and turned it into a nice function:

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

I simplified the best of this answer and turned it into a nice function:

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

tidy up

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edited Mar 10, 2020 at 12:01

Simplified best of simo'sthis answer and turned it into a nice function.:

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

Simplified simo's answer and turned it into a nice function.

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

Simplified best of this answer and turned it into a nice function:

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

added 75 characters in body

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edited Aug 9, 2017 at 12:30

Simplify @simo's answerSimplified simo's answer and turned it into a nice function.

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

Simplify @simo's answer into a nice function.

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

Simplified simo's answer and turned it into a nice function.

function mergeUnique(arr1, arr2){
    return arr1.concat(arr2.filter(function (item) {
        return arr1.indexOf(item) === -1;
    }));
}

Source Link

created Jun 9, 2017 at 17:56

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