An advanced selector request $.level()

[BerkerYuceer]

I was thinking on a tool that would make people's life easier by making a recursive search of elements and give us the deepest level when plainly used.

Level 0
<div id="test">
    Level 1
    <div>
        Level 2
        <div class="third">
            Level 3
            <div>
                Level 4
            </div>
        </div>
    </div>
</div>

It should return level count when no index is given;

$("#test").level(); // Which should return 4

also this should select dom at given level index such as;

$(document).ready(function() {
    var obj = $("#test").level(2);
    alert(obj); // Which should return obj
    alert(obj.attr('class')); // Which should return "third"
});

and when there are more than 1 element at that level should return obj array;

Level 0
<div id="test">
    Level 1
    <div>
        Level 2
        <div class="third">
            Level 3
            <div>
                Level 4
            </div>
        </div>
        <div></div>
        <a></a>
        <img />
        <span> </span>
    </div>
</div>

$(document).ready(function() {
    var obj = $("#test").level(2);
    alert(obj); // Which should return obj array
    alert(obj.length); // Which should return 4 (starting by zero)
});

this would help a lot and solve many turnarounds done with parent(), children(), find() etc..
If its posible to add this feature please contact me (berkeryuceer@yahoo.com).

[rdworth]

This issue queue is for bugs found in pages on the jquery.com website. Your suggestion is more suited to http://forum.jquery.com/