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4 votes
2 answers
287 views

Showing $\int_{-1}^{1}\ln \left( \frac{x+1}{x-1} \right) \left( x - \sqrt{x^2 - 1} \right) \, dx=\frac{\pi^2 + 4}{2}$

While exploring possible applications for exponential substitution, I stumbled upon the following integral identity: $$\int_{-1}^{1}\ln \left( \frac{x+1}{x-1} \right) \left( x - \sqrt{x^2 - 1} \right)...
Emmanuel José García's user avatar
-2 votes
0 answers
141 views

Solving $\sqrt{x+1}=-2$ and looking for complex solutions [duplicate]

So the question was $$\sqrt{x+1}=-2$$ And obviously there is no value for it, However, If you do the thing with $e$ and $\ln{}$ $$e^{\ln{\sqrt{x+1}}}$$ and $$e^{\frac{1}{2}\cdot (\ln{x+1})}$$ Then ...
Jkt's user avatar
  • 19
-4 votes
0 answers
108 views

Find $\arcsin c$, $\, c\in\Bbb C$ [duplicate]

A math fan sent me a solution of the weird equation $\sin z=2$ posted in Quora. It is Weird because in real calculus, we experienced that $-1\leq \sin x\leq 1$. I saw this question in so many places ...
Bob Dobbs's user avatar
  • 11.9k
2 votes
0 answers
87 views

Does complex log(1) have other values than 0?

I want to determine all values of $$ \left[\log \left(3+2 i^{2}\right)\right]^{1-i} $$ First I simplify to $$\left[\log \left(3-2\right)\right]^{1-i}$$ resulting in $$\left[\log \left(1\right)\right]^{...
Eddill's user avatar
  • 21
2 votes
0 answers
74 views

Principal branch of $z^{1-i}$

I am solving a problem Find the principal branch of $z^{1-i}$. I wanted to verify my solution. I know we can write $z^{1-i} = e^{(1-i)\cdot \text{Log}_e(z)}$ Since the principal branch of $\text{Log}...
A. Srivastava's user avatar
0 votes
1 answer
92 views

Conjugate of complex number raised to complex power

Why is $\overline{z^{n}} = (\bar{z})^{n}$ true only for $n \in \mathbb{Z}$? What about a real or complex exponent in general? Let $$\log z=\{\ln \rho + i (\theta + 2k\pi)\mid k\in\Bbb Z\}$$ then $$ \...
Julian's user avatar
  • 1
0 votes
1 answer
125 views

Non-power series proof that $|\log (1 + z)| \le -\log (1 - |z|)$

Given $z \in \mathbb{C}$, $|z| < 1$, we have the bound \begin{align*} |\log (1 + z)| &= \left| \sum_{n \ge 1} \frac{(-1)^{n+1}z^n}{n} \right| \\ &\le \sum_{n \ge 1} \frac{|z|^n}{n} \\ ...
Geoffrey Irving's user avatar
0 votes
1 answer
183 views

The polynomial P(x) is equal to $(i + x)^{2024}$. Let $S$ be the sum of all the real coefficients of $P(x)$. Find $\log_{2} S$. [closed]

I think the answer to this problem is $1012$, but I'm not sure. Any ideas? Any and all help is appreciated.
Ivn's user avatar
  • 119
-1 votes
1 answer
144 views

Calculate $i^{\log(−𝑖)}$ (principal value) [closed]

I am working on a complex number problem and need some guidance on how to calculate the principal value of the expression "$i^{\log(-i)}$". I understand that the principal value of a complex ...
Javad Ibrahimli's user avatar
0 votes
1 answer
51 views

Using the main branch of $z^\lambda$, calculate $1^i$

I do believe this is a simple question, but I am still unsure if my solution correct. We have that: $$z^\lambda=e^{\ln(z)\cdot \lambda}$$ And also that: $$\ln(z)=\ln\left(\sqrt{a^2+b^2}\right) + i\...
soldaluz's user avatar
-2 votes
2 answers
119 views

An integral Wolfram Alpha cannot take: $\displaystyle\int_{-1}^{+1}(-1)^{i\pi e^{-x\pi}}dx$

So I was bored yet again, and decided to evaluate some integrals. After a while, I came up with this:$$\int_{-1}^{+1}(-1)^{i\pi e^{-x\pi}}dx$$which is based off of $\color{red}{\text{this}}$ integral ...
CrSb0001's user avatar
  • 2,652
0 votes
0 answers
37 views

Fast addition of logarithmic values

Given two values $\log(a)$ and $\log(b)$ of complex values $a$ and $b$. Is there a numerically fast way to compute $\log(a + b)$ (on a CPU)? I'm aware that, $\log(a + b) = \log(a) + \log(1 + \exp(\log(...
Jiro's user avatar
  • 577
1 vote
0 answers
46 views

An estimate for a logarithm occuring in analytic number theory

Let $s$ range over the complex numbers and write such numbers as $s=\sigma+iT$ with $\sigma,T$ real. In textbooks on analytic number theory, I have found the following estimate: $$\frac{\log|s|}{|s|} \...
russoo's user avatar
  • 2,436
0 votes
2 answers
99 views

Why is $0≠Log(e^{i2n\pi})=i(2n\pi)$

$\\Log$ denotes the multi-valued natural log defined over the complex numbers I know that $Log(z)$ is multivalued and that we can choose a particular branch if we want to, but why isn't it the case ...
Simon M's user avatar
  • 887
0 votes
0 answers
32 views

Existence and understanding holomorphic root functions

I have to prove that a) for all $|z|<\frac{\pi}{2}$ exists a root function of the function $f(z)=\cos(z)$, which means there is a holomorphic function $g:\mathbb{D}\to \mathbb{C}$, such as $g(z)^2=...
MilesDefis's user avatar

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