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1 vote
1 answer
44 views

Bounding the solution of a logarithmic equation

Given a small number $\varepsilon >0$ and a constant $1/3\le \alpha < 1 $, I am looking for the smallest possible number $x^*$ such that for all real $x\ge \max\{x^*,3\}$, we have $$\frac{x}{(\...
Stratos supports the strike's user avatar
1 vote
2 answers
256 views

Solve $x^x-5x+6=0$ using Lambert W function.

How do I solve $x^x - 5x + 6 = 0$ using the Lambert W function? EDIT: I solved equations $2^x - 5x + 6 = 0$ and $3^x - 4x - 15 = 0$ using Lambert W function, but not able to solve $x^x - 5x + 6 = 0$ ...
Prashant Kumar G's user avatar
1 vote
2 answers
136 views

How to solve $\ln(x) = 3\left(1-\frac{1}{x}\right)$?

I have been working for this problem for a while: $$\ln(x) = 3\left(1-\frac{1}{x}\right)$$ and by graphing, plugging and chugging values and rigorously doing the math, I can clearly see that one of ...
SMK's user avatar
  • 69
3 votes
2 answers
199 views

Need your help in solving $\log_\sqrt[34]{2} x = 4x^4-3x^3-2x^2+x$

I have been playing with graphs until made a nice equation $$\log_\sqrt[34]{2} x = 4x^4-3x^3-2x^2+x$$ The real answers are 1 and 2. But how to solve it? And is it possible to stretch it to complex ...
A PIG's user avatar
  • 39
0 votes
1 answer
65 views

How do you find solutions to the equation $\frac{x}{y^\frac{x}{y}} = 1$, which involves the Lambert W function?

How do you solve for $x$ in the following equation: $$ \frac{x}{y^\frac{x}{y}} = 1 $$ By graphing it, I know there are two real solutions. I tried doing it in the following way: $$ x = y^\frac{x}{y} \\...
RJ Onyx Moonshadow's user avatar
5 votes
2 answers
186 views

Equations similar to Lambert-$W$ with quadratic exponents

I've seen solutions saying that an equation in the format:$$ \ln(x) - \frac{bx}{a} = - \frac{bc}{a} $$ can be solved using the Lambert W function and I am comfortable doing so. My equation however is ...
Charles Brook's user avatar
2 votes
2 answers
133 views

Does the second positive solution (besides $x = 1$) of the equation $e^{x^2-1}=x^3-x\ln x$ have a closed form?

Does the equation $$e^{x^2-1}=x^3-x\ln x$$ have a closed form solution ? The given equation has $2$ positive real roots. Graphically It is not hard to see that $x=1$ is a rational solution. The ...
hardmath's user avatar
  • 644
5 votes
3 answers
238 views

Finding a real closed-form solution to a tricky transcendental equation

One of my friends posed the following question with a prize of free bubble tea for anyone who could find a closed-form solution to the problem (not necessarily in terms of elementary functions): What ...
ojt's user avatar
  • 75
4 votes
6 answers
465 views

How can we find Lambert W solution to $\dfrac {x\ln x}{\ln x+1}=\dfrac{e}{2}$?

Find all real solutions: $$\frac {x\ln x}{\ln x+1}=\frac{e}{2}$$ Cross multiplication gives $$2x\ln x=\ln (x^e)+e$$ I didn't see any useful thing here. I tried solving this equation in WA. The ...
hardmath's user avatar
  • 644
2 votes
4 answers
254 views

How to solve $x + 3^{x} = 4$ using Lambert W Function.

As stated in the title I am trying to solve the equation $$x + 3^{x} = 4$$ using Lambert W Function and which led me to the result $$x = 4 - \frac{W(3^{4} \ln{3})}{\ln{3}}$$ and driven by the belief ...
Michael Stevens's user avatar
2 votes
3 answers
122 views

Showing that $\ln(x)^2+2(x-1)\ln x-3x+1=0$ has only $2$ real solutions

Is there any elementary way to show that $\ln (x)^2+2(x-1)\ln x-3x+1=0$ has $2$ real solutions on $(0,\infty)$? I did it by this way. Let $f(x)=(\ln x)^2+2(x-1)(\ln x)-3x+1$. signs of $f(\frac{1}{2})$...
Stylus's user avatar
  • 35
1 vote
3 answers
161 views

How to rewrite $e^{-x} = -\ln(x)$ such that the Lambert W function can be applied?

Original problem: Find the real solution of $$e^{-x} = -\ln(x)$$ The first thing I did was divide both sides by $e^{-x}$. With a few more steps I arrived at $$e^x\ln(x) = -1$$ This was great, but ...
Pace Shigo's user avatar
1 vote
2 answers
186 views

Closed form for solution of $\ln(x)\ln(x+1)=1 $ [closed]

Is it possible to find a close form for the solution of this equation (maybe with the use of Lambert W function)? $$ \ln(x)\ln(x+1)=1 $$
user967210's user avatar
2 votes
1 answer
127 views

Inverting series with logs and W

You've all heard it: what does a drowning analytic number theorist say? Log log log log.... I very frequently deal with the sorts of functions that one comes across and want to invert them. Generally ...
Charles's user avatar
  • 32.3k
-1 votes
1 answer
199 views

How to solve for $x$ from $x + \ln(x) = \ln(c)$?

How do I solve this equation for P? For everything I've tried, P ends up trapped in an exponent or another natural log. $$ \ln\left(\frac{GC}{a}\right) = hP + \ln(P) $$
Koryak21's user avatar

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