Timeline for Can I intercept a function called directly?
Current License: CC BY-SA 3.0
9 events
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| Nov 29, 2021 at 7:42 | comment | added | cibercitizen1 | Now, ALL function calls can be caught, even if the method being called does not exist. See stackoverflow.com/a/54172062/286335 | |
| Mar 25, 2015 at 3:20 | comment | added | Motomotes |
I wanted to inject an function before another one and I needed to know about this and Function.prototype.call to pass the correct this to my hooked function. developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
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| Aug 14, 2014 at 22:42 | comment | added | Dan |
It's worth noting that someFunction in your example is the function you wish to intercept/extend. I had it backward when I first tried this but eventually figured out I was reading this wrong. Great example besides that.
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| Dec 7, 2011 at 21:51 | history | edited | Andy E | CC BY-SA 3.0 |
added 224 characters in body
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| Aug 4, 2010 at 17:07 | vote | accept | yilmazhuseyin | ||
| Aug 4, 2010 at 14:56 | comment | added | yilmazhuseyin | yes you are right. function newConstructor(){alert("a");}; Function.prototype.constructor = newConstructor; did not work. | |
| Aug 4, 2010 at 14:49 | comment | added | Andy E |
@yilmazhuseyin: no, you can't. Changing the Function constructor would only allow you to override functions created with new Function(str).
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| Aug 4, 2010 at 14:36 | comment | added | yilmazhuseyin | Maybe I can change Function.constructor function so every returned function will have your wrapper around it. | |
| Aug 4, 2010 at 14:29 | history | answered | Andy E | CC BY-SA 2.5 |