233

What is the proper way to get the complete name of month of a DateTime object?
e.g. January, December.

I am currently using:

DateTime.Now.ToString("MMMMMMMMMMMMM");

I know it's not the correct way to do it.

14 Answers 14

347

Use the "MMMM" custom format specifier:

DateTime.Now.ToString("MMMM");
5
  • 3
    If it's only the month you're interested in then DateTime.Today instead of DateTime.Now is a further simplification. No useless time portion and a bit faster.
    – OrizG
    Commented Dec 12, 2017 at 21:58
  • 11
    Surprisingly I'm getting the very text "MMMM"
    – Chagbert
    Commented Jul 5, 2018 at 6:56
  • 1
    DateTime.Now.Month.ToString("MMMM"); will give you "MMMM". Is that what you did? Commented May 22, 2021 at 12:03
  • DateTime.Now.Month.ToString("MMMM") resulted in MMMM string.. not useful Commented Jul 18, 2022 at 1:52
  • Drop the 'Month' portion from your code. Should be: DateTime.Now.ToString("MMMM");
    – Chris W
    Commented Jan 17 at 10:03
105

You can do as mservidio suggested, or even better, keep track of your culture using this overload:

DateTime.Now.ToString("MMMM", CultureInfo.InvariantCulture);
2
  • 3
    That's neat, I need to look into this culture stuff. Commented Jul 20, 2011 at 16:49
  • 2
    If it's only the month you're interested in then DateTime.Today instead of DateTime.Now is a further simplification. No useless time portion and a bit faster.
    – OrizG
    Commented Dec 12, 2017 at 21:58
43

If you want the current month you can use DateTime.Now.ToString("MMMM") to get the full month or DateTime.Now.ToString("MMM") to get an abbreviated month.

If you have some other date that you want to get the month string for, after it is loaded into a DateTime object, you can use the same functions off of that object:
dt.ToString("MMMM") to get the full month or dt.ToString("MMM") to get an abbreviated month.

Reference: Custom Date and Time Format Strings

Alternatively, if you need culture specific month names, then you could try these: DateTimeFormatInfo.GetAbbreviatedMonthName Method
DateTimeFormatInfo.GetMonthName Method

2
  • 1
    +1 for mentioning how to do it from a DateTime that is NOT DateTime.Now. I had thought it was string mon = myDate.Month.ToString("MMM") when I was sadly let down by it spitting "MMM" into my string variable. Glad you took the effort to show how to use .ToString("MMM") on the date, itself, to get the month, when it's not DateTime.Now. And how you explained the difference between MMM and MMMM. Best answer on this page. Kudos.
    – vapcguy
    Commented Oct 7, 2016 at 14:17
  • 1
    If it's only the month you're interested in then DateTime.Today instead of DateTime.Now is a further simplification. No useless time portion and a bit faster.
    – OrizG
    Commented Dec 12, 2017 at 21:55
40

If you receive "MMMM" as a response, probably you are getting the month and then converting it to a string of defined format.

DateTime.Now.Month.ToString("MMMM") 

will output "MMMM"

DateTime.Now.ToString("MMMM") 

will output the month name

19

You can use Culture to get month name for your country like:

System.Globalization.CultureInfo culture = new System.Globalization.CultureInfo("ar-EG");
string FormatDate = DateTime.Now.ToString("dddd., MMM dd yyyy, hh:MM tt", culture);
17

It's

DateTime.Now.ToString("MMMM");

With 4 Ms.

2
  • 1
    If it's only the month you're interested in then DateTime.Today instead of DateTime.Now is a further simplification. No useless time portion and a bit faster.
    – OrizG
    Commented Dec 12, 2017 at 21:57
  • Actually, the time it takes your fingers to type "Now" instead of "Today" is significantly more time saved than cpu cycles saved when using Today.
    – mxmissile
    Commented Apr 23 at 16:41
14
DateTime birthDate = new DateTime(1981, 8, 9);
Console.WriteLine ("I was born on the {0}. of {1}, {2}.", birthDate.Day, birthDate.ToString("MMMM"), birthDate.Year);

/* The above code will say:
"I was born on the 9. of august, 1981."

"dd" converts to the day (01 thru 31).
"ddd" converts to 3-letter name of day (e.g. mon).
"dddd" converts to full name of day (e.g. monday).
"MMM" converts to 3-letter name of month (e.g. aug).
"MMMM" converts to full name of month (e.g. august).
"yyyy" converts to year.
*/
12

It should be just DateTime.ToString( "MMMM" )

You don't need all the extra Ms.

2
Debug.writeline(Format(Now, "dd MMMM yyyy"))
0

You can use the CultureInfo from System.Globalization to get that data, based on the current culture that is being used.

_ = CultureInfo.CurrentCulture.DateTimeFormat.GetMonthName(DateTime.Now.Month)

Or, use InvariantCulture to also get the English name.

_ = CultureInfo.InvariantCulture.DateTimeFormat.GetMonthName(DateTime.Now.Month);
0

if you need three month letter use "MMM"

0

Being a popular question, I stumbled upon the very same question even though my requirement was for the newer DateOnly type.

Fortunately, the same approach is applicable for the newer data type as well.

DateOnly todayDate = DateOnly.FromDateTime(DateTime.UtcNow); //27-08-2023
string fullMonthName = todayDate.ToString("MMMM");
Console.WriteLine(fullMonthName); //August
-1
(DateTime = {07/01/2023 12:00:00 AM})

DateTime.ToString("MMMM")  - ( January )
1
  • 1
    Variants of this answer have already been provided multiple times. When answering older questions, please make sure you provide either a novel solution, or a significantly better explanation than existing answers. Commented Jan 20, 2023 at 11:47
-2

Use this for Full name of the month:

DateTime date = DateTime.Now;
string month = $"{date:MMMM}"; // f.g October

Use this for abbreviation name of the month:

DateTime date = DateTime.Now;
string month = $"{date:MMM}"; // f.g Oct

Use this for full name of the week:

DateTime date = DateTime.Now;
string month = $"{date:dddd}"; // f.g Saturday

Use this for abbreviation name of the week:

DateTime date = DateTime.Now;
string month = $"{date:ddd}"; // f.g Sat

You can set every custom template with this structure f.g:

DateTime date = DateTime.Now;
string month = $"{date:dd/MMM/yyyy}"; // 12/Oct/2022
string month = $"{date:dd-MM-yyyy}"; // 12-10-2022
string month = $"{date:dd MMMM yyyy}"; // 12 October 2022
string month = $"{date:ddd - - - MMM}"; // Sat - - - Oct
string month = $"{date:ddddd $- yyyy}"; // Saturday $- 2022
string month = $"{date:ddMMyyyy}"; // 12102022