1

PHP is giving me a parse error here.

if ($detalleReserva->isGratis() || $detalleReserva->isPasajeroSinCosto()){
    $cantPaxGratis++;
}

Parse error: parse error in /Library/WebServer/Documents/versioned/software/tur/liquidacionHead.php on line 58

The if line is line 58. I've tried changing de || with OR but the same. If I change the second part (after || ) for a '1' or a '0' it works fine.

Extra information:

function isPasajeroSinCosto() {
     return ($this->tipo == 4);
}

PHP version:

PHP 7.1.0 (cli) (built: Dec 2 2016 03:30:24) ( NTS )

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5
  • What is the output from $detalleReserva->isPasajeroSinCosto() ?
    – KhorneHoly
    Commented Feb 12, 2017 at 18:18
  • I've added the function @KhorneHoly
    – user1532587
    Commented Feb 12, 2017 at 18:20
  • if you pasted all the relevant code, maybe just maybe we'd of pasted that in our (code) editors and would have seen that hidden (unicode) character, which I suspect is what it is. Because nothing in what you posted shows it.
    – Funk Forty Niner
    Commented Feb 12, 2017 at 18:40
  • I am not understanding the function isPasajeroSinCosto() because in this function what are you returning? ($this->tipo == 4) is a comparing situation. what will it return?
    – Prateek Verma
    Commented Feb 12, 2017 at 18:56
  • if the class variable tipo is equal to 4, then the function returns true, false otherwise
    – user1532587
    Commented Feb 12, 2017 at 19:18

1 Answer 1

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1

The problem was that I was using mac, and when pressing || and then space to quick (maybe pressing alt), an unknown character (invisible) get into the code and broke it.

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  • 2
    Yes, may I add that || and OR are exactly the same. (you stated that you tried changing that, in your question)
    – Nytrix
    Commented Feb 12, 2017 at 18:26

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