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Questions tagged [logarithms]

Questions related to real and complex logarithms.

4 votes
2 answers
287 views

Showing $\int_{-1}^{1}\ln \left( \frac{x+1}{x-1} \right) \left( x - \sqrt{x^2 - 1} \right) \, dx=\frac{\pi^2 + 4}{2}$

While exploring possible applications for exponential substitution, I stumbled upon the following integral identity: $$\int_{-1}^{1}\ln \left( \frac{x+1}{x-1} \right) \left( x - \sqrt{x^2 - 1} \right)...
Emmanuel José García's user avatar
-2 votes
1 answer
62 views

What is the product of the solutions to the equation (√10)(x^(log (x))) = x^2? [closed]

I have spent a few hours on this question but I can't seem to grasp it. I have found that taking the log of both sides doesn't give me any progress. The log exponent identity didn't work. I also tried ...
shivank chintalpati's user avatar
4 votes
1 answer
178 views

Prove that sequence $(a_n)_{n\geq 1}$ is not convergent.

The standard branch of logarithm, $\log:\mathbb{C}\setminus (-\infty,0]\to\mathbb{C}$ is defined as $$ \log(z):=\ln|z|+i\operatorname{Arg}(z)\tag{2} $$ where $\arg(z)$ is the standard branch of the ...
Max's user avatar
  • 936
0 votes
1 answer
41 views

Integral of Complex logarithm makes sense?

For example, I know that the principal branch of logarithm is not defined over negative real axis. I think the integral of this logarithm along a circle doesn’t make sense. Moreover, I know that the ...
Brody's user avatar
  • 11
1 vote
0 answers
67 views

What does "any polynomial dominates any logarithm" mean here?

My textbook states that any polynomial dominates any logarithm: $n$ dominates $(\log n)^3$. This also means, for example, that $n^2$ dominates $n\log n$ However, it wasn't clear to me what the ...
Princess Mia's user avatar
  • 3,019
-4 votes
0 answers
65 views

Logarithms find the solution

What conditions must $a$ and $b$ satisfy for the equation to have at least one real solution? Find all the solutions of this equation: $1+\log_b(2\log(a)-x)\log_x(b)=2\log_b(x)$ I have tried ...
alan centellas's user avatar
-1 votes
1 answer
100 views

Solve the power equation $\;2\!\cdot\!3^{x^2}=6^x$

Solve the power equation $\;2\!\cdot\!3^{x^2}=6^x.$ $$2 \cdot 3^{x^{2}} = 6^x $$ $$log_3(9) \cdot log_3(3^{x^{2}}) = log_3(6^x) $$ $$2x^2 - xlog_3(6) = 0 $$ $$x(2x - log_3(6)) = 0$$ $$x = 0$$ or $$...
Firefly's user avatar
  • 29
3 votes
1 answer
195 views

Generalizing a logarithmic inequality

Let $\{x_i\}_{i=1}^N$ and $\{y_i\}_{i=1}^N$ be real numbers in the interval (0,1). Define for each $i$ $$\alpha_i = x_i (1-x_i) \log^2 \frac{x_i (1-y_i)}{y_i (1-x_i)}$$ and $$\beta_i = x_i \log \frac{...
mikefallopian's user avatar
2 votes
1 answer
54 views

Prove $\ln (1+x) \leq x - x^2/4 $ for $x \leq 1$ using Taylor's theorem

RTP: $\ln (1+x) \leq x - \frac{1}{4} x^2$ for $x \leq 1$ I am trying to prove this specifically using Taylor theorem. Here is what I have so far: $\ln (1+x) = x - \frac{x^2}{2} + \frac{x^3}{3(1+\xi)^3}...
punypaw's user avatar
  • 487
3 votes
3 answers
385 views

$\operatorname{Li}_{2} \left(\frac{1}{e^{\pi}} \right)$ as a limit of a sum

Working on the same lines as This/This and This I got the following expression for the Dilogarithm $\operatorname{Li}_{2} \left(\frac{1}{e^{\pi}} \right)$: $$\operatorname{Li}_{2} \left(\frac{1}{e^{\...
Srini's user avatar
  • 862
3 votes
2 answers
279 views

A problem that could use substitution or logs, not sure which works better

This is one of those brain teaser problems on instagram, and it starts here: $$x^{x^2-2x+1} = 2x + 1$$ And we want to solve for x. My first instinct was to try this $$\ln(x^{x^2-2x+1}) = \ln(2x + 1)\\ ...
Jesse's user avatar
  • 2,692
3 votes
3 answers
103 views

Why to use modulus in integration of $1/x$ [closed]

$$ \int \frac1x = \log_e |x|+C$$ Why is modulus sign needed. If this is because the domain of logarithmic function is $(0,\infty)$ Then why don't we mention the limitations of the domains of other ...
ca_100's user avatar
  • 199
-2 votes
0 answers
141 views

Solving $\sqrt{x+1}=-2$ and looking for complex solutions [duplicate]

So the question was $$\sqrt{x+1}=-2$$ And obviously there is no value for it, However, If you do the thing with $e$ and $\ln{}$ $$e^{\ln{\sqrt{x+1}}}$$ and $$e^{\frac{1}{2}\cdot (\ln{x+1})}$$ Then ...
Jkt's user avatar
  • 19
1 vote
1 answer
19 views

Rounding to nearest integer in the log domain

This is about the threshold of whether to round down to $N$ or round up to $N+1$ where the proportional rounding error (or the error in the log domain) is smallest. What is the simplest way to prove $$...
robert bristow-johnson's user avatar
1 vote
1 answer
78 views

How to show $(\log_2 x)^4 \leq x^3$ for $x > 1$?

In Rosen's discrete Math textbook, they mention in the solutions for one problem that $(\log_2 x)^4 \leq x^3$ for $x > 1$. However, I'm not sure how to exactly derive that myself, nor does the ...
Bob Marley's user avatar

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